1=x^2+1.2x+0.36

Solution for 1=x^2+1.2x+0.36 equation:

1=x^2+1.2x+0.36

We move all terms to the left:

1-(x^2+1.2x+0.36)=0

We get rid of parentheses

-x^2-1.2x-0.36+1=0

We add all the numbers together, and all the variables

-1x^2-1.2x+0.64=0

a = -1; b = -1.2; c = +0.64;
Δ = b2-4ac
Δ = -1.22-4·(-1)·0.64
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-2}{2*-1}=\frac{-0.8}{-2}
=0.8/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+2}{2*-1}=\frac{3.2}{-2}
=-1+1/1.6666666666667
$